The trapezium rule estimate for 1 0 e x2 dx with h = 0.25 is 1.490

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The trapezium rule estimate for ∫¹₀e^x2dx with h = 0.25 is 1.490 68 to 5dp. Estimate the size of the global truncation error in this approximation and show that

1.40 < = et dx < 1.48 0

What value of h will give an answer correct to 4dp?

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Modern Engineering Mathematics

ISBN: 9781292253497

6th Edition

Authors: Glyn James

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Question Posted: Jan 16, 2024 03:01 AM

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The trapezium rule estimate for 1 0 e x2 dx with h = 0.25 is 1.490

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1.40 < = et dx < 1.48 0

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Modern Engineering Mathematics

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