Writing ln[(x + jy + a)/(x + jy a)] = u + jv, show that (a)

Question:

Writing ln[(x + jy + a)/(x + jy – a)] = u + jv, show that

(a) x + y - 2ax coth u + a = 0 (b) x = a sinh ul(cosh u  cos v) (c) |x + jy| = a(cosh u + cos v)/(cosh u -

Fantastic news! We've Found the answer you've been seeking!

Step by Step Answer:

Related Book For  book-img-for-question
Question Posted: