=+37.15. 1 (a) Show that the probability of no zero in (r, 1) is (2/m) arcsin vt

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=+37.15. 1

(a) Show that the probability of no zero in (r, 1) is (2/m) arcsin vt and hence that the position of the last zero preceding 1 is distributed over (0,1)

with density ₸-1(t(1 -t))-1/2.

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Probability And Measure Wiley Series In Probability And Mathematical Statistics

ISBN: 9788126517718

3rd Edition

Authors: Patrick Billingsley

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Question Posted: Sep 11, 2024 03:00 AM

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=+37.15. 1 (a) Show that the probability of no zero in (r, 1) is (2/m) arcsin vt and hence that the position of the last zero preceding 1 is distributed over (0,1) with density -1(t(1 -t))-1/2.
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=+37.15. 1 (a) Show that the probability of no zero in (r, 1) is (2/m) arcsin vt

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Probability And Measure Wiley Series In Probability And Mathematical Statistics

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