Referring to the previous two problems with the cosine grating oriented horizontally, make a sketch of the electric-field amplitude along y' with no filtering. Plot the corresponding image irradiance distribution. What will the electric field of the image look like if the DC term is filtered out? Plot it. Now plot the new irradiance distribution. What can you say about the spatial frequency of the image with and without the filter in place? Relate your answers to Fig. 11.14.

Fig. 11.14.

fix) = A F(k) A 27A k (b) flx) = A cos kor F(k) TA k Ko +ko (c) fix) = A cos 3kgr F(k) -3ko +3ko 0. fix) = A(1 +cos kr) 2A (d) F(k) 27A k -Ko +Ko (e) fix) = A sin kot F(k) A TA +ko -ko k