Compound A has molecular formula C₈H₈O. An IR spectrum of compound A exhibits a signal at 1680 cm^-1. The¹H NMR spectrum of compound A exhibits a group of signals between 7.5 and 8 ppm (with a combined integration of 5) and one upfield signal with an integration of 3. Compound A is converted into compound B under the following conditions:

When compound B is treated with Br₂ and AlBr₃, two different monobromination products are obtained. Identify both of these products, and predict which one will be the major product. Explain your reasoning.

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Zn [Hg), HCI, heat Compound A Compound B