Consider the computer output shown below. One-Sample Z Test of mu = 30 vs not = 30
Question:
Consider the computer output shown below.
One-Sample Z Test of mu = 30 vs not = 30 The assumed standard deviation = 1.2 N Mean SE Mean 95% CI Z P 16 31.2000 0.3000 (30.6120, 31.7880) ? ?
(a) Fill in the missing values in the output. What conclusion would you draw?
(b) Is this a one-sided or two-sided test?
(c) Use the output and the normal table to find a 99 percent CI on the mean.
(d) What is the P-value if the alternative hypothesis is H1 ∶
???? > 30?
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