The rotatable central composite design. It can be shown that a second-order design is rotatable if n
Question:
The rotatable central composite design. It can be shown that a second-order design is rotatable if
Σn u=1 xa iuxb ju =
0, if a or b or both are odd, and if
Σn u=1 x4 iu = 3
Σn u=1 x2 iux2 ju.
Show that for the central composite design these conditions lead to ???? = (nF)1∕4 for rotatability, where nF is the number of points in the factorial portion.
Fantastic news! We've Found the answer you've been seeking!
Step by Step Answer:
Related Book For
Question Posted: