When air resistance is ignored, it is straightforward to calculate the travel time interval for a Ping-Pong ball tossed up into the air and caught on its way down because the acceleration can be taken to be a constant \(9.8 \mathrm{~m} / \mathrm{s}^{2}\) downward. However, a more accurate result is obtained when air resistance is taken into account. When this is done, is the magnitude of the ball's acceleration greater than, less than, or the same as when air resistance is ignored 

(a) as the ball rises and 

(b) as it falls?

(c) Do you expect the travel time interval obtained in the more accurate analysis to be greater than, less than, or the same as in the simplified case?