A mixture of oxygen and hydrogen is analyzed by passing it over hot copper oxide and through
Question:
A mixture of oxygen and hydrogen is analyzed by passing it over hot copper oxide and through a drying tube. Hydrogen reduces the CuO according to the reaction CuO(s) + H2(g) → Cu(s) + H2O(l), and oxygen reoxidizes the copper formed according to Cu(s) + 1/2O2 (g) → CuO(s). At 25°C and 750. Torr, 172.0 cm3 of the mixture yields 77.5 cm3 of dry oxygen measured at 25°C and 750. Torr after passage over CuO and the drying agent. What is the original composition of the mixture?
Fantastic news! We've Found the answer you've been seeking!
Step by Step Answer:
Related Book For
Question Posted: