Answer Problem P29.3 assuming that “shaved” dice are used so that the number 6 appears twice as often as any other number.

In Problem 29.3

a.

We are interested in the outcome where the sum of two dice is equal to 7. If any side of a die has an equal probability of being observed, then the probability of any number appearing is 1/6.

b.

Using the nomenclature developed above:

c.

Now, one has to sum all the probabilities that correspond to the event of interest:

Psum=7 = [2 (R P6)] + [2 (P P)] + [2 (P3 P4)] 2 1 = 3 36 6