Derive Equations (6.12) and (6.13). Equation 6.12 Equation 6.13 F = Fo cos(ot zVoCp/2K) exp(-zVoCp/2K) Fo

Question:

Derive Equations (6.12) and (6.13).


Equation 6.12


F = Fo cos(ot – zVoCp/2K) exp(-zVoCp/2K)


Equation 6.13


Fo |T = cos(ot — zVоСр/2K — п/4) еxp(-?VоСp/2K).

Fantastic news! We've Found the answer you've been seeking!

Step by Step Answer:

Related Book For  book-img-for-question
Question Posted: