Arrange the following expressions by growth rate from slowest to fastest. 4 n 2 4n2 t log
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Arrange the following expressions by growth rate from slowest to fastest.
- 4n24n2t log3nlog3nT(n)=8n n!n!t 3n3nn 20n20nt 22nlog2nlog2nT(n)=X n2/3n2/3T(2n)=X2
See Stirling’s approximation in Section 2.2 for help in classifying n!n!T(n)=X.
Data From Section 2.2:
Stirling’s approximation states that:
where e ≈ 2.71828 (e is the base for the system of natural logarithms). Thus we see that while n! grows slower than nn (because √ 2πn/en n for any positive integer constant c.
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Related Book For
Practical Introduction To Data Structures And Algorithm Analysis Java Edition
ISBN: 9780136609117
1st Edition
Authors: Clifford A. Shaffer
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