a. Use a CAS to plot the slope field of the differential equation

over the region -3 ≤ x ≤ 3 and -3 ≤ y ≤ 3.

b. Separate the variables and use a CAS integrator to find the general solution in implicit form.

c. Using a CAS implicit function grapher, plot solution curves for the arbitrary constant values C = -6, -4, -2, 0, 2, 4, 6.

d. Find and graph the solution that satisfies the initial condition y(0) = -1.

Transcribed Image Text:

y' 3x² + 4x + 2 2(y - 1)