The equation of a plane in space is 2(x 1) + 4(y 3) (z

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The equation of a plane in space is 2(x − 1) + 4(y − 3) − (z + 5) = 0. What is the normal vector to this plane?

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Calculus Of A Single Variable

ISBN: 9781337275361

11th Edition

Authors: Ron Larson, Bruce H. Edwards

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Question Posted: May 17, 2023 02:00 AM

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The equation of a plane in space is 2(x 1) + 4(y 3) (z

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The equation of a plane in space can be written in the form ax by cz ...View the full answer

Calculus Of A Single Variable

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