=+14.10. Regarding Example 14.6, show that the MLE of satisfies (14.29) (under regularity conditions that you

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=+14.10. Regarding Example 14.6, show that the MLE of ψ satisfies (14.29)

(under regularity conditions that you may need to specify) with a(ψ) = 0 and fj (ψ, yj ), 1 ≤ j ≤ p + q, specified in the example.

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