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A 45-g aluminum spoon (specific heat 0.88 J/g C) at 24 C is placed in 180 mL (180 g) of coffee at 85 C and

A 45-g aluminum spoon (specific heat 0.88 J/g °C) at 24 °C is placed in 180 mL (180 g) of coffee at 85 °C and the temperature of the two become equal.

What is the final temperature when the two become equal? Assume that coffee has the same specific heat as water.

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E mcT Mass of Al 45g Specific heat of Al 088 Jg C T of Al T f T i T 24 ... blur-text-image

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