Generalize your observation. Representing a n?n identity matrix by In and a n?n matrix of ones by On write an inverse for (n + 1)In ? On, it will be in the form of k(In + On). Enter your response by typing % before your answer. Your answer has to be in the form of INV((n + 1)In ? On) = k(In + On). where the k is replaced by the value you choose.

E1 = Seye(4)-ones(4,4) E1 = -1 -1 E1I = inv(E1) E1I = 2/5 1/5 1/5 1/5 E2 = 6 * eye (5)-ones(5,5) E2 = 54444 -1 E21 = inv(E2) E21 = 1/3 1/6 21 1/5 2/5 1/5 1/5 -1 15141 1/6 1/6 1/6 E3 = 3 * eye(2)-ones(2,2) E3 = 1/6 1/3 1/6 1/6 1/6 14 1/5 1/5 2/5 1/5 1/6 1/6 1/3 1/6 1/6 1/5 1/5 1/5 2/5 7777 1/6 1/6 1/6 1/3 1/6 14445 1/6 1/6 1/6 1/6 1/3