0) address starts at 0x2000, but PC=3 (address 0x2003) (1) stack 1 (@1) has value 6 (2) stack 2 (@2) has value 1 (3) command load (0xa0) from 0x2001 to register AX (AX=6), PC=4 (address 0x2004) (4) command store (0xb8) the value in 0x2001 to register BX at 0x8001 (BX=6), PC=5(address 0x2005) (5) command substract (0xc0) the value 1 in 0x2002 from the register AX, PC=6 (address 0x2006) (6) command jump (0x2b) to 0xC=12 if the result in AX is zero, PC=7 (address 0x2007) (7) command store (0xb8) the value into register CX at 0x8006 (CX=5), PC=8 (address 0x2008) (8) command mul (0xf0) the value of register AX by the value in register Bx at 0x8001, AX=5*6=30, PC=9 (address 0x2009) (9) command store (0xb8) the value of register AX in register BX at 0x8001 (Bx=30), PC=10 (address 0x200a) (10) command load (0xa0) the value in register CX at 0x8006 to register AX (AX=CX=5), PC=11 (address 0x200b) (11) command jump (0x20) to address 0x5 (0x2005), PC=5 (address 0x2005) (12) command halt (0x1) is exit. The program looped 6 times to exit.

When exit, AX=0, BX=720, CX=1, DX=0, PC=12, CA = SI= OV = 0, ZE = EV = 1

Lab exercise:

Q1. Click menu , then select . Use this function to step through the assembly code. After the statement in address 11 is first executed, what are the value of registers AX, BX, CX, DX, and PC? Explain the function of AX, BX, CX, DX, and PC. A1: