0 Question 1 v IZ 0/2 pts '0 3 3 19 6) Details You measure 30 randomly selected textbooks' weights, and find they have a mean weight of 49 ounces. Assume the population standard deviation is 11 ounces. Based on this, construct a 99% confidence interval for the true population mean textbook weight. Give your answers as decimals, to two places l IZ 0/1 pt '0 3 2:3 19 G) Details A 95% confidence interval for the weight of a small package of M&Ms is (47.82, 48.16) grams. Which of the following statements best describes the confidence level? 0 There is a 95% chance that a randomly selected package will be in the interval. 0 95% of similar intervals will contain the actual mean weight. 0 There is a 95% chance that the mean weight of packages will be in this interval. 0 95% of package weights are in this interval. 0 Question 12 V E 0/2 pts '0 3 8 19 G Details A student was asked to find a 90% confidence interval for widget width using data from a random sample of size n = 27. Which of the following is a correct interpretation of the interval 11 E 0/2 pts '0 3 2:3 19 (D Details If a school district takes a random sample of 57 Math SAT scores and finds that the average is 457, and knowing that the population standard deviation of Math SAT scores is intended to be 100. Find a 99% confidence interval for the mean math SAT score for this district. SILS 0 Question 3 v IZ 0/2 pts '0 3 8 19 G) Details You measure 35 turtles' weights, and find they have a mean weight of 33 ounces. Assume the population standard deviation is 12.7 ounces. Based on this, construct a 90% confidence interval for the true population mean turtle weight. Round your answers to two decimal places. \\l IZ 0/1 pt '0 3 8 19 G) Details A sample of 58 Charleston County households have a mean income of $21,216 with a standard deviation of $5,536. Find a 90% confidence interval for the true population mean income for households in Charleston County. Round your answers to the nearest dollar. l E 0/1 pt '0 3 8 19 6) Details Karen wants to advertise how many chocolate chips are in each Big Chip cookie at her bakery. She randomly selects a sample of 69 cookies and finds that the number of chocolate chips per cookie in the sample has a mean of 15.7 and a standard deviation of 2.7. What is the 98% confidence interval for the number of chocolate chips per cookie for Big Chip cookies? Enter your answers accurate to one decimal place (because the sample statistics are reported accurate to one decimal place). l l IZ 0/1 pt '0 3 3 19 6) Details You intend to estimate a population mean ,u with the following sample. 52 60.1 36.1 13.6 32.1 57.7 31.6 You believe the population is normally distributed. Find the 95% confidence interval. Enter your answer as an open-interval (i.e., with parentheses and separated by a comma) for example (2.45, 3.69). Round to the nearest hundredth (two places after the decimal). Answer should be obtained without any preliminary rounding. However, the critical value may be rounded to 3 decimal places. Question 7 0/1 pt 9 3 7 19 0 Details We poll 850 people and find that 50% favor Candidate S. In order to estimate with 95% confidence what percent of ALL voters would vote for Candidate S, we should use: O 2-SampTint O 2-PropZInt O 2-SampZInt O ZInterval O TInterval O 1-PropZInt0 Question 8 v I} 0/1 pt '0 3 3 19 G) Details Out of 500 people sampled, 310 had kids. Based on this, construct a 90% confidence interval for the true population proportion of people with kids. Give your answers as decimals, to three places l

E 0/1 pt '0 3 Z 19 G Details Out of 300 people sampled, 213 voted in the last election. Based on this, construct a 90% confidence interval for the true population proportion of people who voted in the last election. Give your answers as decimals, to three places __'