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019 10.0 points What is the moment of inertia about an axis A bicycle tire of radius 0.34 m and mass 2.0 perpendicular to the

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019 10.0 points What is the moment of inertia about an axis A bicycle tire of radius 0.34 m and mass 2.0 perpendicular to the paper and through the kg is rotating at 65.4 rad/s. center of mass? Consider the connecting rod What torque is necessary to stop the tire in to have negligible mass and treat the masses 2.2 s? as point particles. 1. -3.16633 1. 0.28125 2. -11.6667 2. 27.3375 3. -6.4415 3. 0.9 4. -8.09126 4. 11.3535 5. -4.30056 5. 21.801 6. -7.65982 6. 13.182 7. -9.87367 7. 0.73125 8. -6.87295 8. 19.44 9. -2.69724 9. 7.986 10. -7.77673 10. 11.1008 Answer in units of N . m. Answer in units of kg . m 020 10.0 points 018 10.0 points A 49.0 kg uniform solid cylinder has a radius of A uniform rod of length 46 m and mass 15.7 kg 0.136 m. If the cylinder accelerates at is free to rotate about a frictionless pivot at 6.60 x 10 - rad/s' as it rotates about an axis one end in a vertical plane, as in the figure. through its center, how large is the torque acting The rod is released from rest in the horizontal on the cylinder? position. 1. 0.157952 2. 15.7 kg 9.029908 3. -23 m 0.00560227 - 46 m What is the magnitude of the initial angular 0.319851 acceleration of the rod? The acceleration of 5. gravity is 9.8 m/s. 0.0681 156 6. 1. 0.565385 0.788466 2. 0.6125 7. 3. 0.319565 0.352654 4. 1.05 8

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