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=0.652670905RNH3=56791.1128kmol/m3.hrA=706m2FN2=135.43kmol/hrX(0)=0L(0)=0 Question: Solve dLdX=2FN2RNH2A using 4th order Runge Kutta method and plot a Conversion (X) vs Length (L) graph using Excel. Please show a detailed
=0.652670905RNH3=56791.1128kmol/m3.hrA=706m2FN2=135.43kmol/hrX(0)=0L(0)=0 Question: Solve dLdX=2FN2RNH2A using 4th order Runge Kutta method and plot a Conversion (X) vs Length (L) graph using Excel. Please show a detailed working of which values were used how to get the k1, k2 k3 and k4 values using Length =1 as the example Also provide Excel sheet if possible. Note: Please show how to derive the differential equation used for the 4th order Runge Kutta method and what each cell A, B, C, etc. in Excel means too. Answer: =0.652670905HR=3729033.595kJ/molRNH3=56791.1128kmol/m3.hrA=706m2FTotal=555.87kmol/hrCpmix=47.65kJ/kmol.KT(0)=673L(0)=0 Question: Solve dLdT=FTotalCpmix(HR)ARNH3 using 4th order Runge Kutta method and plot a Temperature (T) vs Length (L) graph using Excel. Please show a detailed working of which values were used how to get the k1,k2k3 and k4 values using Length =1 as the example. Also provide Excel sheet if possible. Note: Please show how to derive the differential equation used for the 4th order Runge Kutta method and what each cell A,B,C, etc. in Excel means too
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