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0cm For 2D, the adiabatic ionization energy (v=0+ vt=0 )is 15.000 eV; it's excited by a light that has a wavelength of 58 nm; 2D2
0cm For 2D, the adiabatic ionization energy (v"=0+ vt=0 )is 15.000 eV; it's excited by a light that has a wavelength of 58 nm; 2D2 2D, x'Est , x?E, Te" Te 100097.2 cm2 Te* = 0 cm we" 3115.50 cm We' 1729.92 cm @e* = 1577.3 cm 2 61.82 cm Wexe 34.97 cm @exe* = 32.86 cm B." 29.9037 cm Bo' 15.3891 cm B.* = 14.736 cm B." 28.8251 cm Bi' 14.8212 cm Bi* = 14.176 cm Now, calculate the following: 1) KEs(The electron kinetic energies) that correspond to the formation of ?Dz* (ut= 0) and (v+= 1); 2) The bond lengths for the v+= 0 and 'V"=0 3) The dissociation energy for the ?D?2+x{and 2D, XS; Wexe states states 0cm For 2D, the adiabatic ionization energy (v"=0+ vt=0 )is 15.000 eV; it's excited by a light that has a wavelength of 58 nm; 2D2 2D, x'Est , x?E, Te" Te 100097.2 cm2 Te* = 0 cm we" 3115.50 cm We' 1729.92 cm @e* = 1577.3 cm 2 61.82 cm Wexe 34.97 cm @exe* = 32.86 cm B." 29.9037 cm Bo' 15.3891 cm B.* = 14.736 cm B." 28.8251 cm Bi' 14.8212 cm Bi* = 14.176 cm Now, calculate the following: 1) KEs(The electron kinetic energies) that correspond to the formation of ?Dz* (ut= 0) and (v+= 1); 2) The bond lengths for the v+= 0 and 'V"=0 3) The dissociation energy for the ?D?2+x{and 2D, XS; Wexe states states
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