1 0.2 points An object of mass 3 kg starts from rest and moves along the x-axis. A net horizontal force is applied to the
1 0.2 points An object of mass 3 kg starts from rest and moves along the x-axis. A net horizontal force is applied to the object in +x direction. The force vs. time relationship is presented by the graph below. F(N) 6 A 1 2 3 4 5 6 7 t(5) What is the net impulse delivered by this force? Choose one from the following choices: Show calculations. A. 6 N.S B. 8 N.S C. 24 N.S D. 30 N.S E. 36 N.S Edit View Insert Format Tools Table 12pt Paragraph B IYA & T V EV EV EV TO V VX2 0.2 points A tennis ball of mass 0.25 kg is struck on the wall with an initial velocity of 1.3 m/s and it returns back in the opposite direction with a velocity of -1.1 m/s. Before m = 0.25 kg (v ); = 1.3 m/s The After O (v ) = -1.1 m/s Find: App, J. Answer the following questions: A. Find the change in momentum of the tennis ball given the direction switch on the rebound. B. If the ball was in contact with the wall for 0.25 seconds, what is the magnitude of the force exerted by the wall on the ball?0.4 points & Lump of Clay Colliding with a Hanging Pendulum ball A 20 g piece of clay moves with a constant speed of 15 m/s as shown in the picture. The piece of clay collides and sticks to a massive ball of mass 900 g suspended at the end of a string. The combined mass then swings to a height h. Note 1000 g = 1 kg. Show full calculations. clay piece ) iy Answer the following questions: Calculate the momentum of the piece of clay before the collision. Calculate the kinetic energy of the piece of clay before the collision. What is the momentum of two objects after the collision? Calculate the velocity of the combination of two objects after the collision. Calculate the kinetic energy of the combination of two objects after the collision. Calculate the change in kinetic energy during the collision. Calculate the maximum vertical height, the combination of two objects were able to reach after the collision, using conservation of energy principles from prev1ous chapter. Hint: Here the kinetic energy of the combined mass is converted into potential energy when it reaches height h. OmmONw> Edit View Insert Format Tools Table 0.4 points Combined blocks compress a stationary spring 8 Block 1 with a mass of 500 g moves at a constant speed of 5 m/s on a horizontal frictionless track and collides and sticks to a stationary block 2 mass of 1.5 kg. Block 2 is attached to an unstretched spring with a spring constant 200 N/m. The combined mass (Blocks 1 and 2) compresses the spring by distance x. Block 1 V=5m/s _ Block 2 K =200 N/m Answer the following questions: 1m0 w> Edit . Determine the momentum of block 1 before the collision. . Determine the kinetic energy of block 1 before the collision. . Determine the momentum of the system of two blocks after the collision. . Determine the velocity of the system of two blocks after the collision. . Determine the kinetic energy of the system two blocks after the collision. . Determine the maximum compression (x) in the spring after the collision. View Insert Format Tools Table 0.4 points Collision in 2-dimensions (x- and y-directions) Object A with mass 8 kg travels to the east at 10 m/s and object B with mass 3 kg travels south at 20 m/s. The two objects collide and stick together and then travel. 20 m/s o00 10 m/s Answer the following questions and show full calculations. A. What is the magnitude of the velocity of the combined mass after the collision? Choose one of the following choices for part A. 1.8 m/s 9.1 m/s 12.7 m/s 20 m/s 25.5m/s B. What is the direction of the velocity of the combined mass after the collision? Choose one of the following choices for part B. 30 south of east 37 south of east 45 south of east 53 south of east 60 south of east n 0.4 points g Bullet embedded on a Block mass A 10 g bullet moves at a constant speed of 500 m/s and collides with a 1.5 kg wooden block initially at rest. The surface of the table is frictionless and 70 cm above the floor level. After the collision, the bullet becomes embedded into the block. The bullet-block system slides off the top of the table and strikes the floor. Note 1000g = 1 kg. Answer the following questions: Find the momentum of the bullet before the collision. Find the kinetic energy of the bullet before the collision. Find the velocity of the bullet-block system after the collision. Find the kinetic energy of the bullet-block after the collision. Find the change in kinetic energy during the collision. How long does the bullet-block system take to reach the floor? Find the maximum horizontal distance between the table and the striking point on the floor. OmmOnNw> Edit View Insert Format Tools Table
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