1. [0/4 Points] DETAILS PREVIOUS ANSWERS A proton is acted on by a uniform electric field of magnitude 453 N/C pointing in the positive y direction. The particle is initially at rest. (a) In what direction will the charge move? --Select--- |* What is the direction of the force due to the electric field on the charged particle? (b) Determine the work done by the electric field when the particle has moved through a distance of 2.95 cm from its initial position. (c) Determine the change in electric potential energy of the charged particle. (d) Determine the speed of the charged particle. m/s4. [-/1 Points] DETAILS MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER A disk with uniform surface charge density o = -7.10 JC/mis oriented as shown in the diagram below. The field at a distance y from the center of a disk (of radius r = 0.420 m) and along its axis is given by E = where & = 8.85 x 10-12 C2/(N . m2) is the permittivity of free space. What is the electric potential at a location P whose coordinates are (0, 0.195 m)? Take the electric potential at infinity to be zero. v y P (0, y)5. [-/2 Points] DETAILS MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER (a) What is the magnitude of the electric field in a region where the potential is given by the expression V = ax + b where a = -600 V/m and b = 175 V? (Substitute numerical values, and express your answer in terms of x. Assume SI units, but do not include units in your answer.) V/m (b) What is the magnitude of the electric field at x = 7.75 m? V/m