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A proton is projected in the positive x direction into a region of uniform electric field E = (-6.70 x 105) i N/C att =

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A proton is projected in the positive x direction into a region of uniform electric field E = (-6.70 x 105) i N/C att = 0. The proton travels 7.90 cm as it comes to rest. (a) Determine the acceleration of the proton. magnitude x m/s2 direction -x (b) Determine the initial speed of the proton. magnitude m/ direction +x (c) Determine the time interval over which the proton comes to rest. Submit Answer 3. [0/4 Points] DETAILS PREVIOUS ANSWERS SERPSE10 22.6.P.025.MI. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER A proton moves at 3.60 x 105 m/s in the horizontal direction. It enters a uniform vertical electric field with a magnitude of 8.00 x 105 N/C. Ignore any gravitational effects. (a) Find the time interval required for the proton to travel 6.00 cm horizontally. 1.6E7 X ns (b) Find its vertical displacement during the time interval in which it travels 6.00 cm horizontally. (Indicate direction with the sign of your answer.) mm (c) Find the horizontal and vertical components of its velocity after it has traveled 6.00 cm horizontally. it j km/s Submit Answer 4. [1/2 Points] DETAILS PREVIOUS ANSWERS SERPSE10 23.1.OP.001. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER A rod 16.0 cm long is uniformly charged and has a total charge of -23.0 UC. Determine the magnitude and direction of the electric field along the axis of the rod at a point 36.0 cm from its center. magnitude N/C direction toward the rod Submit Answer 5. [-/4 Points] DETAILS SERPSE10 23.1.OP.002. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER A uniformly charged disk with radius R = 35.0 cm and uniform charge density o = 8.40 x 10- C/m lies in the xy-plane, with its center at the origin. What is the electric field (in MN/C) due to the charged disk at the following locations? (a) z = 5.00 cm MN/C (b) z = 10.0 cm MN/C (c) z = 50.0 cm MN/C (d) z = 200 cm MN/C

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