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1. [-/1 Points] DETAILS SERPSE10 36.A.OP.024. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER A light source shines light consisting of two wavelengths, 1, = 540
1. [-/1 Points] DETAILS SERPSE10 36.A.OP.024. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER A light source shines light consisting of two wavelengths, 1, = 540 nm (green) and 12 = 450 nm (blue), on two slits separated by 0.120 mm. The two overlapping interference patterns, one from each wavelength, are observed on a screen 1.58 m from the slits. What is the minimum distance (in cm) from the center of the screen to a point where a bright fringe of the green light coincides with a bright fringe of the blue light? cm Need Help? Read It Submit Answer 2. [-/1 Points] DETAILS SERPSE10 36.3.OP.012. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER Monochromatic light from two slits forms an interference pattern on a screen. At a certain point on the screen, the intensity of the interference pattern is 72.0% of the maximum. (a) What is the minimum phase difference (in radians) between the light from the slits that produces this result? rad (b) If the wavelength of the light is 484.1 nm, what is the path difference (in nm) that corresponds to this phase difference? nmtwo wavelength - 1, = 540 mm . ( green ) 12 = 450 mm ( blue ) distance both two slits - d = 0'120 mm list of screen - D = 1:58 m The dist of bright fringe from centre : x = 2x D green for = d . for $2 2 = 2 22 D Polue as S 450 540 for minimum - 24 2 5, 3, = 6 5 X XI D d . - 5x 540 x109 ) * 1:58 0 .120 / 1000 ) = 0.035 m. 2 = 3.5 0m . AnsR. 2' intensing at certain point - 72 " of the maximum. 72 100 We know , I= To Cos 72 Cos 100 Ap + phase difference . 72/ 2 A Q = 2X Co 72/100 2 63 . 896 = 67 ' 2 64 x 71 = 1.115 rad And 180 ( b ) 1 = 484 1 mm . phach difference - In phase difference . = 484:1 X 109 X / . 1 15 27 = week 16. 58 Ang
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