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1. [13 Points] SERPSE10 6.3.P.015.MI. 0/6 Submissions Used ASK YOUR TEACHER A person stands on a scale in an elevator. As the elevator starts, the
1. [13 Points] SERPSE10 6.3.P.015.MI. 0/6 Submissions Used ASK YOUR TEACHER A person stands on a scale in an elevator. As the elevator starts, the scale has a constant reading of 584 N. As the elevator later stops, the scale reading is 392 N. Assume the magnitude of the acceleration is the same during starting and stopping. (a) Determine the weight of the person. N (1:) Determine the person's mass. k9 (c) Determine the magnitude of acceleration of the elevator. 2 H m/s Need Help? 2. [-/1 Points] SERPSE10 6.3.P.016. 0/6 Submissions Used ASK VOUR TEACHER A student, along with her backpack on the floor next to her, are in an elevator that is accelerating upward with acceleration a. The student gives her backpack a quick kick at t = 0, imparting to it speed v and causing it to slide across the elevator floor. At time t, the backpack hits the opposite wall a distance L away from the student. Find the coefficient of kinetic friction \"k between the backpack and the elevator oor. (Use any variable or symbol stated above along with the following as necessary: g.) Mk: Need Help? 3. [-/6 Points] DETAILS SERPSE10 6.4.OP.016. 0/6 Submissions Used A skydiver jumps from a slow-moving airplane. The skydiver's mass is 83.0 kg. After falling for some distance, she reaches a terminal speed of 49.5 m/s. (a) What is her acceleration (in m/s2) when her speed is 30.0 m/s? magnitude m/s2 direction ---Select--- (b) What is the drag force (in N) on the skydiver when her speed is 49.5 m/s? magnitude N direction --Select--- v (c) What is the drag force (in N) on the skydiver when her speed is 30.0 m/s? magnitude N direction ---Select--- Need Help? Read It4. [-/3 Points] DETAILS SERPSE10 6.4.OP.020. 0/6 Submissions Used MY NOTES ASK YOUR TEACHER A tugboat is cruising at a speed of 10.1 m/s in still water when it shuts off its engines and coasts to rest. The water exerts drag forces on the tugboat such that its speed during coasting is given by v = ved, where v is the speed at time t, v; is the initial speed at t = 0, and c is a constant. At a time of t = 19.5 s after the engines are cut, the speed is 5.00 m/s. (a) What is the constant c (in s-1) in the expression? (b) What is the speed (in m/s) at t = 40.0 s? m/s (c) Given the expression above for the speed at any time, which of the expressions below gives the tugboat's acceleration while coasting? Oa = -cv O a = -ce-ct O a = cv; O a = ce-ct O a = cv Need Help? Read It5. [-I3 Points] SERPSE1O 6.4.P.020. 0/6 Submissions Used ASK YOUR TEACHER A small piece of Styrofoam packing material is dropped from a height of 2.70 m above the ground. Until it reaches terminal speed, the magnitude of its acceleration is given by a = g Bv. After falling 0.700 m, the Styrofoam effectively reaches terminal speed, and then takes 5.10 s more to reach the ground. (a) What is the value of the constant B? 5'1 (b) What is the acceleration at t = 0? m/s2 (down) (c) What is the acceleration when the speed is 0.150 m/s? m/s2 (down) Need Help
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