$[16$ points$]$ Consider the following portion of memory. Each table cell is a memory location, which

contains a single byte, with values shown in hex, and the address of the rightmost byte on each row

is shown to the right of the row. In this representation of memory, addresses increase as we move

to the left and up in the table.

$($a$)[2$ point$]$ What are the contents of memory location $077$ ad$5f34$ in binary?

$($b$)[2$ point$]$ What are the contents of memory location $077$ ad $5f3e$ in binary?

For each of the following code snippets, which include print $f$ statements, write down what

would be printed out. In each part, assume that p is a pointer of type void $*$ that has the

value $077ad5f34.$

$($c$)[3$ point$]$

int $***a=($ int $*)p$;

printf$(\frac{?}{?}\%x,*a)$;

Output: $?$

$($d$)[3$ point$]$

char $***b=($ char $***)p$;

printf$(\frac{?}{?}\%c,***(b+2))$;

Output: $?$

$($e$)[3$ point$]$

char $***c=($ char $***)p$;

printf$(\frac{?}{?}\%s,c)$; $[16$ points$]$ Consider the following portion of memory. Each table cell is a memory location, which

contains a single byte, with values shown in hex, and the address of the rightmost byte on each row

is shown to the right of the row. In this representation of memory, addresses increase as we move

to the left and up in the table.

$($a$)[2$ point$]$ What are the contents of memory location $077$ ad$5f34$ in binary?

$($b$)[2$ point$]$ What are the contents of memory location $077$ ad $5f3e$ in binary?

For each of the following code snippets, which include print $f$ statements, write down what

would be printed out. In each part, assume that p is a pointer of type void $*$ that has the

value $077ad5f34.$

$($c$)[3$ point$]$

int $***a=($ int $*)p$;

printf$(\frac{?}{?}\%x,*a)$;

Output: $?$

$($d$)[3$ point$]$

char $***b=($ char $***)p$;

printf$(\frac{?}{?}\%c,***(b+2))$;

Output: $?$

$($e$)[3$ point$]$

char $***c=($ char $***)p$;

printf$(\frac{?}{?}\%s,c)$;

Output: $?$

$($f$)$ point$]$

long $***d=($ long $**)p$;

printf$(\frac{?}{?}\%lx,**(d+1))$;

Output: $?$

Output: $?$

$($f$)$ point$]$

long $***d=($ long $**)p$;

printf$(\frac{?}{?}\%lx,**(d+1))$;

Output: $?$

I already know $1$a is $"01000010",1$d is $"$U$",1$e is "BYU cs is cool!"