1. A 0.2880 g sample of KHP required 21.75 mL of a NaOH solution to reach the phenolphthalein end point. Determine the molarity of the NaOH solution. 2. 3. KHP+NaOH->KNaP+HO Imole I mole # of moles of KHP = 0.2880g 204. 22 g mol/KHP 10/=21.75/1000=0.02175L =0.00141 mol/0021752 =0.0649m NaOH m = 0.0649 m V = 22.40ml 22.40 mL of the NaOH solution described in Question 1 was required to titrate 25.00 mL of acetic acid. Determine the concentration of the acetic acid. M V = MV m = m = 1 MiV V Later the student used the above NaOH solution to titrate 20.0 mL of a sulfuric acid solution (HSO4). Calculate the molarity of the sulfuric acid solution knowing that 33.45 mL of the NaOH solution were required to reach the end point