1. A block of mass = 15.0 kg is on a rough ides surface. A force F = 95 N is exerted on the block at an angle of 0 = 250 with respect to the F com horizontal, as shown in the figure. The block is moving. Between the block and the floor, the exte coefficient of kinetic friction is Uk = 0.50. m a. What is the gravitational force on the lifte block due to the earth (magnitude and Ctheexpertfa.com direction)? -2250 a95N 2 m Ew= mg ng LW = (15.0)(9.8) = 147N b. In the coordinate system shown, what are the components of the vector F ? CUS FX= 95cos ( 250) sin 95 sin (25)0 al = 86.09 N = 40.14N c. What is the normal force of the floor pushing up on the block? 140. 1487 N D FN = mgsin (x) = 195 sin (259) - 15 EM cOSX d. What is the friction force on the block (magnitude and direction)? ff = MK ( FN ) .. Ff = (0 . 50 ) ( 40. 14 ) = 2807 N e. What is the acceleration of the block? E F = 43. 0496N ZF = 95cos 250 - (0.50) 195 (85 250) 4 31 0 496 = 15a = ( 2 6 86 q m / s ? ) EF= 86.09 - 43. 0496 = 43. 0496 bicyclist and bike have a total mass of 70.0 kg and they accelerate from rest at 0.25