1. A boat is 50.0 m from the base of a cliff, fleeing at 5.0 m/s. A gun, mounted on the edge of the cliff fires a shell at 40.0 m/s and hits the boat when it has fled another 50.0 m. See the diagram below. v = 40.0 m/s 4 H P 50.0 m 50.0 m (a) At what angle above the horizontal must the gun be aimed so that the shell will hit the target? (4) (b) How high is the cliff? (3) (c) With what velocity does the shell hit the boat? (4) Fs 1 = 4d HS = FN 4t Fk 4v HK = FN a = At FNET = ma V1 + 12 Vavg = Fc = mac 2 of = vi + at ac Ad = (Us+vi) At ac = r(2 nf) 2 Ad = vit + = dAt2 ac = r T 1 Ad = v.At - =dAt2 F = r Fe = mr(2nf)2 BAZ = viz+ 2aAd -b+ Vb2 - 4ac F = mr T X= 2a