1. A hot solution of Ba(NO3)2 from an evaporator contains 30.6kgBa(NO3)2/100kg H2O and goes to a crystallizer where the solution is cooled and Ba(NO3)2 crystallizes. 10% of the water present is lost through evaporation. For a feed solution of 100kg total, calculate the following. (a) The yield of crystals if the solution is cooled to 290K, where the solubility is 8.6kgBa(NO3)2/100kg total water. (b) The yield if cooled instead to 283K, where the solubility is 7.0kgBa(NO3)2/100 kg total water Mw(Ba(NO3)2)=261.34kg/kmol Mw (water) =18kg/kmol