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1. A woman walks eastward tor l5 km. and the 23 km 45 degrees north east. How far is she from the starting point? If
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A woman walks eastward tor l5 km. and the 23 km 45 degrees north east. How far is she from the starting point? If she had walked directly to her destination, in what direction would she have headed? A. The woman is 36.24 km for from her starting point. If she walked directly to her destination, she would be headed 27.48 degrees north east. B. The woman is 35.24 km for from her starting point. If she walked directly to her destination, she would be headed 27.48 degrees north east. C. The woman is 36.24 km for from her starting point. if she walked directly to her destination, she would be headed 2848 degrees north east. D. The woman is 35.24 km far from her starting point. If she walked directly to her destination, she would be headed 28.48 degrees north east. Determine the vertical and horizontal component of the force as illustrated in the figure below. F= 200 lbs. 0 30 What is the Y component of F? A. 100.3 lbs. B. 100.2 lbs. C. 100.0 lbs. D. 100.7 lbs.From the figure below, find T1 and T2 50 20 VW = lord lbs A. 652.9 lbs. and 879.40 lbs. B. 652.9 lbs. and 879.39 lbs. C. 651.08 lbs. and 877.29 lbs. D. 651.08 lbs. and 877.19 lbs.Determine the vertical and horizontal component of the force as illustrated in the figure below. F= 200 lbs. 0 30 What is the Y component of F? A. 100.3 lbs. B. 100.2 lbs. C. 100.0 lbs. D. 100.7 lbs.A boy weighs 400 Newton (N). He sits in a swing as shown in the figure below. Rope 2 rapes of the swing 0 70 T2 W = 400 N What is the value of T2? A. 145.59 N B. 146.59 N C. 147.59 N D. 148.59 NA 5 and 8 kg mass are fastened at both end of 2-m long uniform bar as shown in the figure below. The bar itself weighs 6 kg. Where could a single force R be applied to balance the system, and how great is the magnitude would the R have to be? F1= 5kg Fa = 8kq Im C A W= 6k X A. The fulcrum with a force of 19 kg must be placed at a distance of 1.84 m from point A to make the bar in equilibrium. B. The fulcrum with a force of 19 kg must be placed at a distance of 1.158 m from point B to make the bar in equilibrium. C. The fulcrum with a force of 19 kg must be placed at a distance of 0.84 m from point A to make the bar in equilibrium. D. The fulcrum with a force of 19 kg must be placed at a distance of 1.158 m from point A to make the bar in equilibrium.A 300 - lb. box is held at rest on a smooth incline by a force P making an angle 45\" with the incline plane as shown in the figure below What is the value of P? A. 210 lbs. B. 212Ibs. C. 214 lbs. D. 216 lbs. The body on the 3CDD inclines in the figure below is acted upon by a force F inclined at 20 with the horizontal. If P is resolved into components parallel and normal to the incline and the value ofthe parallel component P1. is 300 lbs. '5' I; : 300 lb; What is the value of force P? A. 467.62Ibs. B. 466.72lbs. C. 476.63 IDS. D. 466.37Ibs. The body on the 30 inclines in the gure below is acted upon by a force F inclined at 20 with the horizontal. If P is resolved into components parallel and normal to the incline and the value ofthe parallel component P, is 300 lbs. ' a = 300 lb;. 2\" p What is the value of angle A. 200 B. 600 c. 300 o. 500 A boy weighs 400 Newton (N). He sits in a swing as shown in the figure below. Rope 2 rapes of the swing 0 th 70 W = 400 N What is the value of T? A. 422.67 N B. 423.67 N C. 424.67 N D. 425.67 NThe body on the 30 inclines in the gure below is acted upon by a force F inclined at 20 with the horizontal. If P is resolved into components parallel and normal to the incline and the value ofthe parallel component P; is 300 lbs. 7 F; = 300 '95\". .'.' P What is the vertical component of farce P? A. 357.53 lbs. B. 355.53 lbs. C. 356.53 lbs. D. 358.53 lbsStep by Step Solution
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