1. Balance: Fe(OH), Mg(NO) Fe(NO) + Mg(OH) 20(OH)2 + 3Mg(NO3)2= 2Fe(NO3)3+3 Mg(OH)2 Nitrate ion & hydroxide ion 3 mol Mg(NO3)2 need amol of fe(OH)3 (3.6 mol x 2mol)/3 mol = 2.4 mol fel0473 3. If you have 3.6 mols Mg(NO), how many mols of Fe(OH), are needed to completely react? 4. If you have 150 g Fe(OH), how many grams of Mg(OH)2 can be produced? 150g/106.867 g/mol = 1.4 mol 5. If have 2.4 mols Mg(NO) and 3.8 mols Fe(OH), what is the limiting reagent? you 2.105 mol x 58.3197 g/mol = 102 .8 gratis 6. How much of each product can be produced? 7. How much excess reagent remains unreacted? 8. f76.5 g Fe(NO), is produced from 250g Mg(NO), what is the percent yield