Question
1. Calculate the hydrogen ion concentration,[H + ], for the two weak acids(pH=-log[H + ], or [H + ]=antilog(-pH). If you have difficulty finding or
1. Calculate the hydrogen ion concentration,[H+ ], for the two weak acids(pH=-log[H+ ], or [H+ ]=antilog(-pH). If you have difficulty finding or using the antilog functionon your calculator, simply use this:[H+ ]=10-pH .
2. Calculate the hydroxide ion concentration,[OH- ], for the weak base using this formula:pOH=14-pH, then [OH- ]=antilog (-pOH) or[OH-]=10-pOH.
3. Calculate the molar concentrations of the vinegar as well asammonia. Both are industry standard 5.00% by mass solutions inwater. This means 5.00 g of solute/ 100.00 g of solution. Assumethat the solution is mostly water (which it is) and thus has adensity of 1.00 g H2O/1.00 ml H2O. Now usethis information plus the molar masses of the vinegar (acetic acid)and ammonia (ammonium hydroxide) to change the 5.00 g solute/100.00g solution to M, which is mol solute/L solution (H2O).Record these concentrations in your data table.
4. Calculate the Ka or Kb usingthe formula given in the introduction.
5.Calculate the pKa orpKb (pKa/b =-logKa/b)
Reagents | pH level |
Table Salt (NaCl) | 7.33 |
Washing Soda (Na2CO3) | 10.89 |
Smelling Salts ((NH4)2CO3) | 7.77 |
Epsom Salt (MgSO4) | 9.50 |
Vinegar (acetic acid, CH3COOH) | 2.21 |
Seltzer Water (carbonic acid,H2CO3) | 3.97 |
Ammonia (ammonium hydroxide,NH4OH) | 10.57 |
Seltzer: H+ concentration | 0.000107 |
Vinegar: H+ concentration | 0.006166 |
Ammonia: OH- concentration | 0.000372 |
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