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(1) CIO (aq) + H2O(1) = HCIO(aq) + OH(aq) (2)(aq) + HCIO(aq) - HIO(aq) + C (aq) (3) OH(aq) + HIO(aq) - H2O(l) +10 (aq)

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(1) CIO (aq) + H2O(1) = HCIO(aq) + OH(aq) (2)(aq) + HCIO(aq) - HIO(aq) + C (aq) (3) OH(aq) + HIO(aq) - H2O(l) +10 (aq) (fast) [slow) [fast] (a) What is the overall equation? Select the single best answer. OCIO (aq) + (aq) --- IO (aq) + H2O(1) + Cl(aq) OCIO (aq) + (aq) = 10" (aq) + C (aq) OCIO (aq) + (aq) + 10 (aq) + Cl(aq) CIO (aq) + (aq) = 10 (aq) + H2O(1) +CF (aq) (b) Identify the intermediate(s), if any. Select the single best answer. o No intermediates OHCIO, OH, HIO, H,O C.OH,r, CO,10 o HCIO, OH,HIO (c) What are the molecularity and the rate law for each step? Select the single best answers. (1): rates bimolecular ky([HCIO||OH (HCIO(OH) termolecular . [HCOOH unimolecular ki(CIO 1,01 (2): rate bimolecular termolecular kal][HCIO k[HO][CI] Okz([HIO][ CHCIO) unimolecular (3): rate bimolecular Az[H0][107 *3[OH HIO termolecular unimolecular Ry([H0][10 DOHHOD (d) Is the mechanism consistent with the actual rate law: rate [CIO 1)

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