Answered step by step
Verified Expert Solution
Question
1 Approved Answer
1 Complete the code to iterate through the keys and values of the car_prices dictionary, printing out some information about each one. 1. def car_listing(car_prices):
1 Complete the code to iterate through the keys and values of the car_prices dictionary, printing out some information about each one. 1. def car_listing(car_prices): result = "" 3- for : result += "{} costs {} dollars". _ + " " return result 7 print(car_listing({"Kia Soul":19900, "Lamborghini Diablo":55000, "Ford Fiesta" :13000, "Toyota Prius":24000})) 2 Use a dictionary to count the frequency of letters in the input string. Only letters should be counted, not blank spaces, numbers, or punctuation. Upper case should be considered the same as lower case. For example, count_letters("This is a sentence.") should return ('t': 2, 'h': 1, 'i': 2, 's': 3, 'a': 1, 'e': 3, 'n': 2, 'c': 1}. 1 - def count_letters (text): 2 result = {} # Go through each letter in the text for letter in : # Check if the letter needs to be counted or not # Add or increment the value in the dictionary return result print(count_letters ("AaBbcc")) # Should be {'a': 2, "b': 2, 'c': 2) print(count_letters ("Math is fun! 2+2=4")) # Should be {'m': 1, 'a': 1, 't': 1, 'h': 1, 'i': 1, 's': 1, 'f': 1, 'u': 1, 'n' 17 17 18 print(count_letters ("This is a sentence.")) # Should be {'t': 2, 'h': 1, "i': 2, 's': 3, 'a': 1, 'e': 3, 'n': 2, 'c': 1)
Step by Step Solution
There are 3 Steps involved in it
Step: 1
Get Instant Access to Expert-Tailored Solutions
See step-by-step solutions with expert insights and AI powered tools for academic success
Step: 2
Step: 3
Ace Your Homework with AI
Get the answers you need in no time with our AI-driven, step-by-step assistance
Get Started