$1.$Concentration of NO is to be reduced by passing it through a bed of spherical porous solid pellets. The reaction is of first order. A $2\%$ A$-98\%$ air mixture flows at a rate of $1{10}^{-6}\frac{m^3}{s}$ through a $50\mathrm{.}8$mmID pipe packed with porous solid. The reaction is as follows:

Calculate the weight of catalys and reactor length to reduce the concentration of NO to $0\mathrm{.}004\%.$

Kinematic viscosity, $v=1\mathrm{.}53{10}^{-8}\frac{m^2}{s}$;$D_{AB}=2{10}^{-8}\frac{m^2}{s}$;$D_e=1\mathrm{.}82{10}^{-8}\frac{m^2}{s}$;$,$ density $=1400k\frac{g}{m^3}$; $R=$ radius of catalyst $=3mm,lon=0\mathrm{.}5,[C=$ density of particle$=2800k\frac{g}{m^3}=2\mathrm{.}8{10}^6\frac{g}{m^3}$