1. Consider the following chemical equilibria in aqueous solution: CO2(aq) + H2O + H2CO3 (1) CO, (aq)+H,0 H+ + HCO3 (2) Ka [H* |(HCO31 -4.45 x 10-7 pK 1 =6.35 [CO] HCO PH+ +CO- (3) K; = [H*][co1 = 4.69 x 10" PK 2 = 10.33 [HCO3) CaCO3 + H2O + CO2 + Ca2+ Ksp = 4.6x109 (4) (5) CO32- + H2O + HCO3 + OH- Kb = 2.1x10-4 Keg CaCO3(s) + H2O + Ca2+ + HCO3 + OH (6) a) Based on eq. (4), calculate the molar solubility of calcium carbonate for a saturated solution in water. b) Calculate the molar solubility of calcium carbonate by consideration of eq (5) according to the following equilibrium expression, eq (6). c) Why does the value of the molar solubility according to eq. (6) differ from that obtained by eq. (5). How can you explain the difference based on Le Chateilier's principle