Question
1. Consider the following two way table that summarizes two variables in a dataset no yes Total New version 4980 5020 10000 old version 5020
1. Consider the following two way table that summarizes two variables in a dataset
no | yes | Total | |
New version | 4980 | 5020 | 10000 |
old version | 5020 | 4980 | 10000 |
The variables are "which version of the product? old or new" and "would they buy it? yes or no"
use the p-value calculator to find find the p-value that measures evidence for the claim that there is a relationship between variables.
You just need to enter the p-value , but it is useful to understand that the p-value is based on the test stat which is a zscore if the difference between population proportions is 0 in this case that test stat is 0.56568542494924 if the test stat is correct then the p-value is correct.
2.Consider the following data set
At the Sydney store a sample of 100 customers spent an average of $2206 with standard deviation $60
and at the Melbourne store a sample of 100 customers spent an average of $2208 with standard deviation $80
What is the p-value for testing if there is a difference between means
use software such as
http://www.usablestats.com/calcs/2samplet&summary=1
click here for a guide to usigng the webpage
or use the p-value calculator
guide to using the p-value calculator
Click here for a guide for using the p-value calculator
if you enter the numbers correctly the test stat should be -0.2
There are many p-values in the output, Always use the first p-value in the output,
3. Be careful with this question, you must tick every correct option Compare and contrast both cases below, use the p-value calculator
click here for a guide for using the p-value calculator CASE1
group 1 | group 2 | |
mean | 100.97 | 99.71 |
standard deviation | 30 | 40 |
sample size | 100 | 100 |
Test stat =0.252 (Use a computer to verify this test stat, if the test stat is correct then the p-value is correct)
CASE 2
group 1 | group 2 | |
mean | 100.97 | 99.71 |
standard deviation | 30 | 40 |
sample size | 400 | 400 |
Test stat =0.504 (Use a computer to verify this test stat, if the test stat is correct then the p-value is correct)
a.the sample proportion in group 1 is 14.37
b.for case 1 the pvalue is 6.65
c.for case 1 the pvalue is 0.80
d.For case 2 the pvalue is =0.81
e.For case 2 the pvalue is =0.61
f.When you compare case 1 with case 2, case 2 has a larger sample size so there is more evidence that the population means are different so the p-value is lower
g.When you compare case 1 with case 2, case 2 has a larger sample size so there is more evidence that the population means are different so the p-value is higher
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