1. Could you please provide the artist with the volume of a Krispy Kreme doughnut and a formula for the general volume of the doughnut shape in case he needs to make larger or smaller versions? 2. Furthermore, could you determine the weight of the bronze doughnut? To do so, you may need to know that, due to the way the bronze hardens and is cured, the density changes as a function of the distance from the center of the doughnut According to the function: Density = B.BDe"-D.(15x Where it = 0 represents the very center of the doughnut, as shown in Figure B and the density is measured in grams per cubic centimeter. Here is the answer for number 1. I need number 2. The volume of a Krispy Kreme donut can be given by the following equation: VKdonut = 1 ( (V1.75 - 27 + 2.75 )2 - ((-V1.75 - 27 + 2.75 ) 2 ) ) did Which will give us the answer of 166.241 cm3. This works because we define a circle between the outside of the donut, and the donut hole. This circle is where all of the delicious donut is. We then take an infinitesimal amount of the circles and rotate them around the x-axis, and taking a sum of all these circles is what gives us the volume of our donut. (0, 4.5) Here is a graph of our donut where the red perimeter is the outside of the donut and the green perimeter is where the (0, 2.75) donut hole is. The blue circle represents a cross section of the donut ring, which is the circle we talked about earlier. (-4.5, 0) (0. 1) ( 4.5, 0) (0, -1) (0, -4.5) A generalized formula to find the volume of a donut is the following: V donut = Where, (12 -1) r = Radius of the donut hole, 2 = Radius of the whole donut, I; = 2 ("2+1) Additionally, if we make a new variable, "R", and set it equal to 2 , we can rewrite the integral to be easier to integrate. Integration will give us the answer of: Vdonut = mrs . 2nR