1. double price1 = 10.10, price2 = 10.12, price3 = 10.15; int cents1 = (int)(price1 * 100); int cents2 = (int)(price2 * 100); int cents3 = (int)(price3 * 100); printf("%d 10.10 = %.15lf ", cents1, price1); printf("%d 10.12 = %.15lf ", cents2, price2); printf("%d 10.15 = %.15lf ", cents3, price3); Briefly explain why the cents2 variable doesn't properly represent the total cents of price2.

2.You had to use integer division (/) to get the number of coins and the modulus (%) operator to easily obtain the remainder amount after each coin denomination calculation. Let's assume this program needed to be modified to only determine the breakdown of paper bills ($50, $20, $10, $5). Provide the few lines of code that would be required to demonstrate how the $20 denomination would be calculated (use your solution variables in your example). 3.Displaying total cents in the format of dollars and cents (ex: 7245 to $72.45) required converting (casting) an integer to a floating-point type (along with a simple calculation). Without changing any variable data types, show three (3) different ways to accomplish the same outcome (use your solution variables in your example). If you are having problems thinking of how to approach this, think about how an expression can be promoted or narrowed in several ways based on explicit casting, coercion, and how each operand plays a role in this determination.