/ 1 dx, letting u = x(In(x))8 In(x), we have found du dx. = 1 To solve the integral Notice the term 1 1 x(In(x))8 dx = dx is included in the integral, so we can rewrite the given integral in terms of u and du. 1 8 | (In (x))) ( 1 dx (In(x)) x = 1 (In(u))8 du