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1 dy 2 Using S = 2ny x with la dx y= ex and dy = dx we have S = 2ny 1 + dx

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1 dy 2 Using S = 2ny x with la dx y= ex and dy = dx we have S = 2ny 1 + dx dx = 2n e 3 x 1 + 9ex dx 326 = 9 1 + u2 du (where u = 3e3x) 3 IN = 9 sec3(0) do (where u = tan(0), a = tan-1(3e6), and B = tan-1(3)) a 9 + In(|sec(0) + tan(0)1) (by this example) B = 9 sec(a) tan(a) + In(sec(a) + tan(a)) - 3\\ 10 - In( v 10 + 3). Since tan(a) = 3e, we have sec (a) = 1 + tan (a) = 1 + 9e12 and S = 9 3ev 1 + 9e12 + In( 3e6 + \\ 1 + 9e12 ) - 3\\ 10 - In(V 10 + 3)

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