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1) Event A occurs with probability 0.2. Event B occurs with probability 0.49, and P(A U B) = 0.63 Find: a) P(A n BC) b)
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Event A occurs with probability 0.2. Event B occurs with probability 0.49, and P(A U B) = 0.63 Find: a) P(A n BC) b) P(An B) c) P(A | B) d) P(B' | A) e) P(A U B)The NIH is creating a test for the Zika virus. The incidence of a Zika is low, 10 percent in the general population. There is a trial version, but it sometimes misses the disease. The probability of a false negative is 0.13. Similarly, someone who does not have Zika, will sometimes get a positive reading. The probability of this is 0.3. Fill in the tree diagram and ... Answer as a decimal to 4 decimal places. D = event that someone actually has Zika positive = event that a test states that a person has Zika Marginal Conditional Probabilities Probabilities Joint Probabilities P(positive | D) P(D and positive) False negative P(D) P(negative | D) P(D and negative) False Positive P(no D) P(positive | no D) P(no D and positive) P(negative | no D) P(no D and negative) Calculate the probability that a positive test result implies that someone has ZikaStep by Step Solution
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