_\\___ .._.. .1- F-..._I. For a SIMILAR system: The diagram shows a uniformly:r charged, non-conducting sphere. The sphere is directlyI above a uniformly:r charged, non-conducting ring. The sphere and ring NOW HAVE have equal charges of -Q_ Now. what is the magnitude and direction of the Electric Force acting on the sphere? Remember: The radius of the ring, R I 40cm z I 50 cm Magnitude of Q I20 1.\": O o O The same magnitude as before with the SAME direction 0 The same magnitude as before but in the OPPOSITE direction 0 Twice the magnitude as before but in the OPPOSITE direction 0 Twice the magnitude as before with the same direction For the same system: The diagram shows a uniformlyr charged, non-conducting sphere. The sphere is directlyI above a uniformlyr charged, non-conducting ring. The sphere and ring NOW HAVE have equal charges of -Q. Assume that the sphere 'Is held in perfect equilibrium at the height of: above the center of the ring. What is the mass of the sphere? Remember: The radius of the ring. R I 40 cm 2 I 50 cm Magnitude of Q I20 {JC 0 6.35 kg 0 0 0 Cannot be solved without the mass of the ring. 0 9.8 kg 00.?kg