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Find the inverse of the function y = 2 log.(4x + 1) - 6 (x+6 4 O B) y = 4 (0.5x+3) -1 4 X+6 O c) 4 log4 y = O Dy = (4+6) 2 ( E) y = 105x+3 - 1Find the inverse of the function y = (23x+1) - 1 O A) y = log? (3x+3)-1 3 O B) y = logz (3x+1)-1 3 O c) y = log2 (x + 1) - = O D) y = 108, (3x +1) - 1 3 ( E) y = 3 log,(x)+1 - 1 3Solve the following equation 3* = WIN O A) x = 10g3 WIN ( B) x = = O C) x = log WIN OD) x = E) x = 10g3True or False? log. (M) = logb logM A) True O B) FalseTrue or False? log,(M + P) = logM + log P A) True ( B) FalseTrue or False? log2(2x) = 1 +log2(x) A) True ( B) FalseWrite as a single logarithm. 2 + =logs(x - 1) - 3 logs(2z) + = logs(v) - logs(a) A) 1085 25+(x-1) 05+12/3 -823 -a (B) 1085 25vx-1y2/3 8a 28 O C) 1085 2(x-1)05 2 223- a OD) 1085 2+(x-1)0.5 2/3\\ -22 a ( E) 1085 25 (x-1)1/2, 2/8 -2azIn ideal conditions, an E. coli bacteria population can double in 17 minutes (for example: 100 bacteria would divide and become 200 bacteria). Using this growth rate, if a person eats a meal with 8 E. coli bacteria, how many bacteria will be in the person after 12 hours? (Assume all bacteria survive and no antibiotics are taken). Use at least 5 digits in your calculations and report your answer to 2 significant digits. Stats source: http://textbookofbacteriology.net/growth_3.html. O A) 4.5 x 1013 bacteria 0 B) 5.6 x 101' bacteria 0 C) 9.2 x 1018 bacteria 0 Dl 13 bacteria 0 El 92 bacteria The half-life of an antidepressant in an average male patient is 36 hours. How many hours does it take for 85% of the original dose to be eliminated from an average male patient's body? Use at least 5 significant digits in all your calculations and round your final answer to 3 significant digits. O A) 98.5 h 0 B) 30.6 h 0 C) 61.6 h 0 D) 42.4 h 0 E) 8.44 h Write as a sum or difference of multiples of logarithms. Evaluate logarithms where possible. log 12(73 - 10) Vx 100w4 A) 2 log(y) + 3log(rvx) -log(10\\x) -2-4log(w) O B) 2 log(v) + 3log(r) - log(10) + =log(x) - log(100) - 4log(w) O C) 2 log(y) + log(r3 - 10) + = log(x) - 2-4log(w) O D) 2 log(y) + 3log(r - 10) + =log(x) - log(100) -4log(w) OE) 2 log(v) + log(73 - 10) + =log(x) - 6log(w)