Question
1) Find the value of z such that the area between -z and +z is 97.6% of the total area under the standard normal curve.
1) Find the value of z such that the area between -z and +z is 97.6% of the total area under the standard normal curve.
A. 2.25
B. 1.96
C. 2.58
D. 2.36
E. 2.26
2) The scores on a certain test are normally distributed with mean 61 and standard deviation 3. What is the probability that a sample of 100 students will have a mean score more than 61.3?
A. 0.4602
B. 0.3413
C. 0.8413
D. 0.1587
E. none of the above
3) A random sample of 66 observations was taken from a large population. The population proportion is 12%. The probability that the sample proportion will be more than 17% is
A. 0.0568
B. 0.8944
C. 0.1056
D. 0.4222
E. None of the above
4) .Assume a Normal Distribution with mean = 98.7 and IQR = 0.67. Find the standard deviation.
A. 0.37
B. 0.45
C. 0.50
D. 1.50
E. none of the above
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