1. 1. For the following problem, develop the z-row after substituting out the artificial variables:

Max z = 2x₁ – 7x₂

Subject to

–2x₁ + 3x₂ = 3

4x₁ + 5x₂≥ 10

6x₁ + 7x₂≤ 3

4x₁ + 8x₂≥ 5

x₁, x₂≥ 0

Max z = 2x₁ – 7x₂

2. For the following problem, develop the z-row after substituting out the artificial variables:

Min z = 3x₁ + 6x₂

Subject to

x₁ + 2x₂≤ 5

6x₁ + 7x₂≤ 3

4x₁ + 8x₂≥ 5

x₁, x₂≥ 0