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1. Given hashing method below, fill the hash codes for each block. Prove that deletion and insertion breaks the integrity of the chain. f(genesisblock)f(otherblocks)=AmountRoundUp(NumberOfLetters(Payee)(NumberOfLetters(Payeer))2)=2f(previousblock)+AmountRoundUp(NumberOfLetters(Payee)(NumberOfLetters(Payeer)2) 2.
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